Optimal. Leaf size=548 \[ \frac{5 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^3}{48 b c \left (c^2 x^2+1\right )^{5/2}}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{24 \left (c^2 x^2+1\right )}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{16 \left (c^2 x^2+1\right )^2}-\frac{b \sqrt{c^2 x^2+1} (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{18 c}-\frac{5 b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{48 c \sqrt{c^2 x^2+1}}-\frac{5 b c x^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{16 \left (c^2 x^2+1\right )^{5/2}}+\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{65 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1728 \left (c^2 x^2+1\right )}+\frac{245 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1152 \left (c^2 x^2+1\right )^2}-\frac{115 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sinh ^{-1}(c x)}{1152 c \left (c^2 x^2+1\right )^{5/2}}+\frac{1}{108} b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \]
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Rubi [A] time = 0.611743, antiderivative size = 548, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 9, integrand size = 37, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.243, Rules used = {5712, 5684, 5682, 5675, 5661, 321, 215, 5717, 195} \[ \frac{5 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^3}{48 b c \left (c^2 x^2+1\right )^{5/2}}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{24 \left (c^2 x^2+1\right )}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{16 \left (c^2 x^2+1\right )^2}-\frac{b \sqrt{c^2 x^2+1} (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{18 c}-\frac{5 b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{48 c \sqrt{c^2 x^2+1}}-\frac{5 b c x^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{16 \left (c^2 x^2+1\right )^{5/2}}+\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{65 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1728 \left (c^2 x^2+1\right )}+\frac{245 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1152 \left (c^2 x^2+1\right )^2}-\frac{115 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sinh ^{-1}(c x)}{1152 c \left (c^2 x^2+1\right )^{5/2}}+\frac{1}{108} b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \]
Antiderivative was successfully verified.
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Rule 5712
Rule 5684
Rule 5682
Rule 5675
Rule 5661
Rule 321
Rule 215
Rule 5717
Rule 195
Rubi steps
\begin{align*} \int (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2 \, dx &=\frac{\left ((d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \left (1+c^2 x^2\right )^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2 \, dx}{\left (1+c^2 x^2\right )^{5/2}}\\ &=\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{\left (5 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \left (1+c^2 x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )^2 \, dx}{6 \left (1+c^2 x^2\right )^{5/2}}-\frac{\left (b c (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int x \left (1+c^2 x^2\right )^2 \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{3 \left (1+c^2 x^2\right )^{5/2}}\\ &=-\frac{b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{18 c}+\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{24 \left (1+c^2 x^2\right )}+\frac{\left (5 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2 \, dx}{8 \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \left (1+c^2 x^2\right )^{5/2} \, dx}{18 \left (1+c^2 x^2\right )^{5/2}}-\frac{\left (5 b c (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int x \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{12 \left (1+c^2 x^2\right )^{5/2}}\\ &=\frac{1}{108} b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}-\frac{5 b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{48 c \sqrt{1+c^2 x^2}}-\frac{b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{18 c}+\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{16 \left (1+c^2 x^2\right )^2}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{24 \left (1+c^2 x^2\right )}+\frac{\left (5 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{\sqrt{1+c^2 x^2}} \, dx}{16 \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (5 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \left (1+c^2 x^2\right )^{3/2} \, dx}{108 \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (5 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \left (1+c^2 x^2\right )^{3/2} \, dx}{48 \left (1+c^2 x^2\right )^{5/2}}-\frac{\left (5 b c (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int x \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{8 \left (1+c^2 x^2\right )^{5/2}}\\ &=\frac{1}{108} b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}+\frac{65 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1728 \left (1+c^2 x^2\right )}-\frac{5 b c x^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{16 \left (1+c^2 x^2\right )^{5/2}}-\frac{5 b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{48 c \sqrt{1+c^2 x^2}}-\frac{b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{18 c}+\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{16 \left (1+c^2 x^2\right )^2}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{24 \left (1+c^2 x^2\right )}+\frac{5 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^3}{48 b c \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (5 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \sqrt{1+c^2 x^2} \, dx}{144 \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (5 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \sqrt{1+c^2 x^2} \, dx}{64 \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (5 b^2 c^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \frac{x^2}{\sqrt{1+c^2 x^2}} \, dx}{16 \left (1+c^2 x^2\right )^{5/2}}\\ &=\frac{1}{108} b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}+\frac{245 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1152 \left (1+c^2 x^2\right )^2}+\frac{65 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1728 \left (1+c^2 x^2\right )}-\frac{5 b c x^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{16 \left (1+c^2 x^2\right )^{5/2}}-\frac{5 b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{48 c \sqrt{1+c^2 x^2}}-\frac{b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{18 c}+\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{16 \left (1+c^2 x^2\right )^2}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{24 \left (1+c^2 x^2\right )}+\frac{5 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^3}{48 b c \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (5 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \frac{1}{\sqrt{1+c^2 x^2}} \, dx}{288 \left (1+c^2 x^2\right )^{5/2}}+\frac{\left (5 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \frac{1}{\sqrt{1+c^2 x^2}} \, dx}{128 \left (1+c^2 x^2\right )^{5/2}}-\frac{\left (5 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2}\right ) \int \frac{1}{\sqrt{1+c^2 x^2}} \, dx}{32 \left (1+c^2 x^2\right )^{5/2}}\\ &=\frac{1}{108} b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}+\frac{245 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1152 \left (1+c^2 x^2\right )^2}+\frac{65 b^2 x (d+i c d x)^{5/2} (f-i c f x)^{5/2}}{1728 \left (1+c^2 x^2\right )}-\frac{115 b^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sinh ^{-1}(c x)}{1152 c \left (1+c^2 x^2\right )^{5/2}}-\frac{5 b c x^2 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{16 \left (1+c^2 x^2\right )^{5/2}}-\frac{5 b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )}{48 c \sqrt{1+c^2 x^2}}-\frac{b (d+i c d x)^{5/2} (f-i c f x)^{5/2} \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{18 c}+\frac{1}{6} x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{16 \left (1+c^2 x^2\right )^2}+\frac{5 x (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^2}{24 \left (1+c^2 x^2\right )}+\frac{5 (d+i c d x)^{5/2} (f-i c f x)^{5/2} \left (a+b \sinh ^{-1}(c x)\right )^3}{48 b c \left (1+c^2 x^2\right )^{5/2}}\\ \end{align*}
Mathematica [A] time = 2.24734, size = 735, normalized size = 1.34 \[ \frac{2304 a^2 c^5 d^2 f^2 x^5 \sqrt{c^2 x^2+1} \sqrt{d+i c d x} \sqrt{f-i c f x}+7488 a^2 c^3 d^2 f^2 x^3 \sqrt{c^2 x^2+1} \sqrt{d+i c d x} \sqrt{f-i c f x}+9504 a^2 c d^2 f^2 x \sqrt{c^2 x^2+1} \sqrt{d+i c d x} \sqrt{f-i c f x}+4320 a^2 d^{5/2} f^{5/2} \sqrt{c^2 x^2+1} \log \left (c d f x+\sqrt{d} \sqrt{f} \sqrt{d+i c d x} \sqrt{f-i c f x}\right )+72 b d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \sinh ^{-1}(c x)^2 \left (60 a+45 b \sinh \left (2 \sinh ^{-1}(c x)\right )+9 b \sinh \left (4 \sinh ^{-1}(c x)\right )+b \sinh \left (6 \sinh ^{-1}(c x)\right )\right )-3240 a b d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \cosh \left (2 \sinh ^{-1}(c x)\right )-324 a b d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \cosh \left (4 \sinh ^{-1}(c x)\right )-24 a b d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \cosh \left (6 \sinh ^{-1}(c x)\right )-12 b d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \sinh ^{-1}(c x) \left (-540 a \sinh \left (2 \sinh ^{-1}(c x)\right )-108 a \sinh \left (4 \sinh ^{-1}(c x)\right )-12 a \sinh \left (6 \sinh ^{-1}(c x)\right )+270 b \cosh \left (2 \sinh ^{-1}(c x)\right )+27 b \cosh \left (4 \sinh ^{-1}(c x)\right )+2 b \cosh \left (6 \sinh ^{-1}(c x)\right )\right )+1440 b^2 d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \sinh ^{-1}(c x)^3+1620 b^2 d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \sinh \left (2 \sinh ^{-1}(c x)\right )+81 b^2 d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \sinh \left (4 \sinh ^{-1}(c x)\right )+4 b^2 d^2 f^2 \sqrt{d+i c d x} \sqrt{f-i c f x} \sinh \left (6 \sinh ^{-1}(c x)\right )}{13824 c \sqrt{c^2 x^2+1}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.266, size = 0, normalized size = 0. \begin{align*} \int \left ( d+icdx \right ) ^{{\frac{5}{2}}} \left ( f-icfx \right ) ^{{\frac{5}{2}}} \left ( a+b{\it Arcsinh} \left ( cx \right ) \right ) ^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b^{2} c^{4} d^{2} f^{2} x^{4} + 2 \, b^{2} c^{2} d^{2} f^{2} x^{2} + b^{2} d^{2} f^{2}\right )} \sqrt{i \, c d x + d} \sqrt{-i \, c f x + f} \log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )^{2} + 2 \,{\left (a b c^{4} d^{2} f^{2} x^{4} + 2 \, a b c^{2} d^{2} f^{2} x^{2} + a b d^{2} f^{2}\right )} \sqrt{i \, c d x + d} \sqrt{-i \, c f x + f} \log \left (c x + \sqrt{c^{2} x^{2} + 1}\right ) +{\left (a^{2} c^{4} d^{2} f^{2} x^{4} + 2 \, a^{2} c^{2} d^{2} f^{2} x^{2} + a^{2} d^{2} f^{2}\right )} \sqrt{i \, c d x + d} \sqrt{-i \, c f x + f}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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